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1903 Iowa gubernatorial election

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1903 Iowa gubernatorial election

← 1901 November 3, 1903 1906 →
 
Nominee Albert B. Cummins J. B. Sullivan
Party Republican Democratic
Popular vote 238,804 159,725
Percentage 57.14% 38.22%

County results
Cummins:      40-50%      50-60%      60-70%      70-80%      80-90%
Sullivan:      40-50%      50-60%

Governor before election

Albert B. Cummins
Republican

Elected Governor

Albert B. Cummins
Republican

The 1903 Iowa gubernatorial election was held on November 3, 1903. Incumbent Republican Albert B. Cummins defeated Democratic nominee J. B. Sullivan with 57.14% of the vote.

General election

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Candidates

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Major party candidates

  • Albert B. Cummins, Republican
  • J. B. Sullivan, Democratic

Other candidates

  • John F. Hanson, Prohibition
  • John M. Work, Socialist
  • Luman Hamlin Weller, People's

Results

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1903 Iowa gubernatorial election[1]
Party Candidate Votes % ±%
Republican Albert B. Cummins (incumbent) 238,804 57.14%
Democratic J. B. Sullivan 159,725 38.22%
Prohibition John F. Hanson 12,375 2.96%
Socialist John M. Work 6,421 1.54%
Populist Luman Hamlin Weller 594 0.14%
Majority 79,079
Turnout
Republican hold Swing

References

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  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved August 3, 2020.